y = k/x2
x2y= k = 22 *10 = 40
x2 y = 40
x2 (4000) = 40
x2 = 1/100
x = 1/10
a1 + 3d = 8 8-3d = a1
a1 = a2 - (a2 +d) - a1 = d
8 - (3*-a1) =a1
8 + 3a1=a1
8 = -2a1
a1 = -4 d = 4
-4 0 4 8
First auto has a 2 x 60 = 120 mile headstart
Closing speed of the second auto is 80 - 60 = 20 m/hr it will take 120 m / 20 m /hr = 6 hours to catch the first auto
Multiply numerator and denominator by sqrt (245) to get
6 sqrt 245 / 245
a = 4 b
c = 2b-7
b summed = 180
4b + 2b-7 + b = 180 solve for b then a = 4b and c = 2b-7
First ...expand the given equation to a x^2 + b x + c form
then the maximum will occur at x = - b/ 2a
use this value of 'x' in the equation to calculate the max value of the function.......
d = dimes value = 10d
q = quarters = 36-d value = 25 (36-d) summed , these two = 420
10 d + 25(36-d) = 420 solve for d = the number of dimes ...then quarters = 36 - d
1 cent plus 5 cents + 10 cents = 16 cents 26 cents left and 9 coins left On more dime two more nickles and 6 more pennies
pennies 7
nickels 3
dimes 2
x^2 > 1/2
x > sqrt (1/2) x < sqrt 1/2
sqrt .5 = .707
from .707 to 1 and from -1 to -.707 is a total of .58579 out of a span of 2 = .293 29.3 %
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