x^( ) * x^6 = x^9 divide both sides by x^6 =
x^( ) = x^9 / x^6
x^( ) = x^3 .....therefore......the "blank" exponent must equal "3"
3x^2 * 3x^2 =
3 * 3 * x^2 * x*2 =
9x^4 .....remember the rule......a*m * a^n = a^(m + n).....!!!
(-5)^2 == (-1)*(5)*(-1)*(5) = (-5)*(-5) = 25
But
-5^2 = -1(5)^2 = -1*(5)*(5) = -25 !!!!
This is a common error...in the first case the exponent applies to the "understood" -1 in front of the "5"....in the second case, the exponent only applies to the 5 itself, not to the "understood" -1....be careful, here !!!
3√(a2) x 4√a =
a^(2/3) x a^(1/4 ) =
a^(2/3 + 1/4) =
a^(11/12) =
12√(a11) in radical form
We need to see a diagram.....you have to register in order to post those......
Mmmmm.....an "e" ????
Thanks, Anonymous....I gave a "truncated" pi value.....thus.....your answer is a little closer to the truth.....!!!!
pi ≈ 3.14......so we have
(3.14)x = 74 take the log of both sides
log(3.14)x =log (74) and, by a log property, we can write
x log(3.14) = log(74) divide both sides by log(3.14)
x = log(74) / log(3.14) ≈ 3.76156
Using polynomial division, we have
x^2 - (1/3)x + (26/9)
3x - 4 [ 3x^3 - 5x^2 + 10x - 3]
3x^3 - 4x^2
------------------
-1x^2 + 10x
-1x^2 +(4/3)x
-------------------
(26/3)x - 3
(26/3)x - (104/9)
---------------------
(77/9)
So.....the answer is.......... [ x^2 - (1/3)x + (26/9) ] + [ 77/9]/[3x - 4]
Too much, Anonymous !!!
65.47 = 6.547 x 101
