Here's (a)
If m has exactly 5 positive divisors.....there can only be one prime factor....to see why....
Let's suppose m can be prime factored as.....a^p * b^q , ......the number of possible divisors of m is (p +1)(q + 1) and we assume that p and q ≥ 1.......then the number of possible divisors cannot be 5 because there are no two integers p, q ≥ 1, such that (p +1)(q + 1) = 5 .....
Similarly, if m factored as some number of primes greater than two, the least number of possible divisors would be eight... (Example......if a, b and c were primes each to the first power, the least number of divisors would be .... 2 * 2 * 2 = 8 )
Therefore, if m has 5 positive divisors, then it can only have one prime factor - and this has to be to the 4th power......( Example ... 2^4 = 16 .... and it has 5 positive divisors......1, 2, 4, 8, 16......)
