If 5x - 4y = 7 and xy = 6 find 125x^3 - 64y^3
Note (5x - 4y)^2 = 7^2 → 25x^2 - 40xy + 16y^2 = 49 → 25x^2 + 16y^2 = 49 + 40xy
So....factoring 125x^3 - 64y^3 ..... we have..
(5x - 4y) (25x^2 + 20xy + 16y^2) =
(5x -4) ([25x^2 + 16y^2] + 20xy) =
(7) ([ 49 + 40xy ]+ 20xy) =
(7)(49 + 60xy) =
(7)(49 + 60(6) ) =
(7) (49 + 360 ) =
(7)(409) =
2863
