I think you're saying
C(20, n) + C(20,10) = C(21, 11) if so....subtract C(20,10) fom both sides
C(20,n) = C(21, 11) - C(20, 10)
C(20, n) = 167960
And ... C(20, 9) = 167960 and therefore..... C(20, 11) equals the same
So...the sum of these "n's" = 9 + 11 = 20
I think that's correct, Mellie
