(x^4)^5/(x^3)^3= x^20 / x^9 = x^11
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(a^2b^3/ab^2)....I'm going to assume this is (a^2b^3)/(ab^2).... if so, we have
(a^2)/(a) * (b^3)/(b^2) =
a * b =
ab
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(2/3)^-3×(a^3/b)^-2.......notice that we can use this"trick' to get rid of the negative exponents.....
(3/2)^3 * (b/a^3)^2 ....so we have...
(27/8) * (b^2 / a^6) =
(27b^2)/(8a^6)
