Melody actually didn't quite carry her calculations far enough.
We have
(n-3)(n-2)(n-1)n ≥ 8760
n4 - 6n3 + 11n2 - 6n ≥ 8760
Using WolframAlpha ...we get the following (somewhat messy) solution....
n ≥ (3/2) + (1/2)* sqrt(5 + 4√8761) =
n ≥ about 11.239
Which confirms that we need more than 11.... (which means 12)
Her way is actually superior to my "guess and check" approach....!!!
But.....as she always says..."All roads lead to Rome"
