I'll try this one, too
Ada could choose any of 9 gifts and the other 9 people have 9! ways to choose theirs. Note that some of these include the possibiiity that Billy does draw his own gift.
After she draws hers, we want to look at the total scenarios that have Billy "stuck" with his own gift.
In this scenario, Ada draws 8 gifts (since she doesn't draw her own, nor Billy's)....and the other 8 people have 8! ways of choosing amongst the remaining 8 gifts. Notice that some of these include the possibility that they actually draw their own gifts, but that's not a stated consideration.
So ... P[ Billy draws his own gift l Ada doesn't draw her gift ] =
[8 * 8! ] / [9 * 9!] = (8/9)(1/9) = 8/91 ..... the same as found by Melody....
