CPhill

Yeah, rosala....you're correct.....I applied it at the end to convert the decimal to a percent......it should be 100%, though......not just 100...!!!

We have 26 letters and we want to choose any 5 of them.....this is given by the combination......

C(26,5)  = 65,780  ways.... (different sets)

We have

C(13,11)(.7)^11(.30)^2 + C(13,12)(.7)^12(.30)^1 + C(13,13)(.7)^13(.3)^0   =

about 20.2%

1102.25=1000(1+r)^2/100

We don't need the 100, rosala

1102.25=1000(1+r)^2        divide both sides by 1000

1.10225 = (1 + r)^2            take the square root of both sides

1.0499  = 1 + r                   subtract 1 from both sides

.0499 = r    =  about 5%

Er....one pile....???

HAHAHAHA!!!....that's great Anonymous.....!!!!

ROFLMAO....!!!!!

Well...that depends on how big the hole is.......maybe they're digging to China...LOL!!!

Very nice, Anonymous.....

25sinxcosx-5sinx+20cosx= 4

Following your lead....

25sinxcosx + 20cosx = 4 + 5sinx

5cosx(5sinx + 4) = (5six + 4)

5cosx = 1

cosx =1/5  at 78.46°

And the other value where sin x = (-4/5) is  about 233°

So...that's all our angles on [0,360]

Perimeter of rectangle  ... 2(a + b)

Perimeter of square = 4a

Perimeter of triangle = b + 2√[(1/2b)^2 + h^2] = b + 2√[(1/4)b^2 + h^2]

Perimeter of parallelogam = 2[ b  + side length]  ....this is all we can do on this one, rosala

Perimeter of circle 2 * pi * b

P.S. - If the triangle is equilateral.....then Anonymous' answer is correct......we're not told if it is or not.....!!!

7/4(3x-1/2)-4/3<5/3    add 4/3 to both sides

(7/4)[3x -(1/2)] < 9/3

(7/4)[(3x - (1/2)] < 3     multiply both sides by 4

7[3x - (1/2)] < 12          divide through by 7

3x - 1/2  < 12/7             mutiply throgh by 14

42x - 7 < 24                   add 7 to both sides

42x < 31                       divide both sides by 42

x < 31/42