CPhill

I believe this is y = 4 l x l + 9

Not a proof....but notice....

3! = 4!/4

2!  = 3!/3

1! = 2!/2

So....this would imply that

0!  = 1! / 1  = 1/1 = 1

(16)((x^2+1)^3))(1-3x^2)

The only thing that makes this 0 is found in the last term

We have

1 - 3x^2 = 0      add 3x^2  to both sides

1 = 3x^2          divide bpth sides by 3

1/3 = x^2          take the square root of both sides

±√(1/3)  = x  

And these are the two values that make this function = 0

2 * (x - 10) = x   simplify

2x - 20  = x        add 20 to both sides and subtract x from both sides

x = 20

............................................................................................................................

We know the hypotenuse - 40 - and an angle = 60. And we're looking for the opposite side. The sine relates these......so we have

sine 60 = opp / 40

(√3/2) *40  = opp = 20√3 ft. = about 34.64 ft.

Define number a so that the straight that goes through points (-1,3) and (3,a). the straights slope is 2:3

So we have

[3 - a] / [-1 -3 ] = 2/3

[3 -a ] / -4 = 2/3     cross-multiply

3(3 -a) = -8    simplify

9 - 3a  = -8     subtract 9 from both sides

-3a  = -17        divide both sides by -3

a = 17/3

(-3 1/4) ( 3 1/5)

-3 1/4 = -13/4

3 1/5  = 16/5

So we have

(-13/4) (16/5) =

"Cancel" the 4 and 16

(-13)(4/5) =

-52/5

You can use the " ^ " key on your keyboard in the onsite calculator.....

Use the  " x^y " key on the calculator or the " ^ " key on the keyboard....

Caution.....the calculator will take small bases to a large power like this......(I think it will handle "e"), but it will balk at raising larger bases to powers like this.