CPhill

It's a repeating decimal with a cycle length of six  → .571428

120 is the outlier....it's clearly larger than any of the other data values.......

(3 + 1/30) / (1/6)  =

(10 / 3) / (1 /6)   =

(10 / 3) x ( 6 / 1) =

60 / 3 =

20

The sine reaches a maximum at 90°

Here's a graph

This can't be determined.....the plane could have been at any height.....we would have to know the descent angle to calculate the answer to this question.......{although 15,000 seems most reasonable }

a ferry sets sail from an island located at (4,12) on a map. its destination is ferry landing b at (6,2).how far will the ferry travel if each unit on the grid is 0.5 mile?

Using the distance fromula, we have

D =√[(4 - 6)^2 + (12 - 2)^2] =

√[4 + 100]=

√104=

2√26 units

And since each unit is.5 miles we just need to divide this by 2 to get

√26 miles ≈ 5.099 miles

(x + y + z) (xy + xz + yz) =

[x^2(y + z) + y^2(x + z) + z^2(x + y)] + 3xyz = 18

                             6                             +  3xyz = 18   subtract 6 from both sides

                                                                3xyz = 12    divide by 3 on both sides

                                                                  xyz = 4

1/64 = 1/2^6    1/512 = 1/2^9   ..so we have..

(1/2^6)^x  = (1/2)^9 =

(1/2)^(6x) = (1/2)^9      we have like bases, so equating exponents, we have

6x =9   divide by 6

x = 9/6 = 3/2

m + 1/m = 8    square both sides

m^2 + 2(m)(1/m) + 1/m^2  = 64

m^2 + 2 + 1/m^2 = 64    subtract 2 from both sides

m^2 + 1/m^2  = 62  ....therefore

m^2 + 1/m^2 + 4 = 62 + 4   = 66

So we have

 N^2 + N + N^(1/3) = 759

Let's assume that the number we're looking for is an integer.

And let's first take the sq root of 759 = about 27.55

Then 759  is a little larger than 27^2

Let's test 27

27^2 + 27  + 27^(1/2) =

729 + 27 + 3  = 

759

So.....27 is the integer we were looking for....