CPhill

Don't feel bad, rosala...I agree...the more help...the better!!!!

[Plus....getting those points is ALWAYS a good thing  !!! ]

[x/(x-8)]+8=[8/(x-8)]

The easiest way to do this is to subtract [x/(x-8)] from both sides and write 8 as 8/1.....so we have

8/1 =[8/(x-8)] - [x/(x-8)] =

8/1 = (8 - x)/(x-8)    but the right side = -(x -8)/ (x-8) = -1

And 8 can never = -1   .....so this has no solution

1 + 2/3 = 5/3

So we have

5/3  /  60/1

Remember, that when we divide fractions, we change to multiplication and "flip" the second fraction.....

You should be able to take it from there

S = .90pr   where S = the sales tax

Just key in ".5" and hit the "=" sign.

These answers all have the same decimal part .....the only diffenence is in the integer part of their evaluation. The integer part tells us the exponent on "10" when we write the given antilog in scientific notation.

Thus

3 = 10^.477 = 3 x 10^0

30 = 10^1.477 = 3 x 10^1

etc.

Using the Pythagorean Triple, 5, 12, 13, y = 12.....however, in the 4th quadrant, y would be negative.....so we have

csc Θ = r / y   =  13/-12 = -13/12   and

tan Θ = y / x = -12 / 5

Here's my take on this one......

We're just counting sets of things, and order witin sets doesn't matter, so this is a combination problem, rather than a permute problem.

The number of possible sets made by choosing any 3 b***s from 9 =C(9,3) = 84

And the number of possible sets made by choosing no black b***s is just C(6,3) = 20

So, the number of possible sets made by choosing at least one black ball = 84 - 60 = 64

{I'm not great at probability, so I really don't know if i'm correct, ot not....!!!}

[32^(1/5)]^5  =

[2]^5  =

32   !!!

X-1      X+2

---- +  -----  = 7

  3          6

Getting a common denominator we have

(2(x -1) + x+2) / 6 = 7    multiply both sides by 6

2(x-1) + x + 2  = 42  simplify

2x - 2 + x + 2 = 42

3x = 42     divide both sides by 3

x = 14