CPhill

sin^-1 = the inverse sine.....just go to the onsite calculator and hit the"2nd" button, then...hit the "asin" button, key in the value you'd like to find, and hit "enter"

2x-19+19=13+19   simplify this on both sides

2x = 32      divide both sides by 2

x = 16

a)     ³√b  = b^(1/3) ....so we have

b^(1/3) / b^(1/6)   ....remember  a^m / a^n = a^(m-n)...so we have  b^(1/3 - 1/6)  = b^(1/6)

b)  (x^3)^2 * y^(-2) / xy   =    x^6 / [x y^2 *y] = x^5 / y^3      .....remember a^(-n)  = 1 / a^(n)....also (a^m)^n  = a^(m x n)

c) a^3 x b^4 x a ^4 x a^3  = a^10 x b^4  ...  the rule is a^n * a^m = a^(n+m)

668ml per 8 sec   = 83.5ml per second......so multiply this by 60 to get your answer.....

"i' is an "imaginary" number......it has the property that  i^2 = -1  or, to put it another way, i =√-1

So we have

√(-64) = √[(-1)(64)] = √(-1)*√64  = i*8  or just 8*i  = 8i

Does that make sense??

8.80  =  8 + 80/100  = 8 + 8/10 = 8 + 4/5  = 44/5

Here you go....

Since 1/2 of the cards are red ones, then the chances of draawing a red card is just 1/2 or .50

Tangente inversa de (500/300)

tan-1 (500/300) = tan-1 (5/3) = 59,036243467926 ° .... recuerde, esto también podría ser un ángulo cuadrante tercero = 239,036243467926 °.

(-1,-2) and (2,2)

1st, subtract the x's and square the result...so we have  (-1-2)^2 = (-3)^2 = 9

Now, do the same for the y's  .....(-2-2)^2  = (-4)^2  = 16

(Note that the order in wich we subtract doesn't matter)

Add the two results   = 25

Take the square root of this  ...√25 = 5  ...and that's the distance