The sum of any three angles in a triangle = 180
Just sum each of the choices......any sum that doesn't equal 180 is out of the club...!!!
It can't be the last two because
9 + 2 < 15
And
3 + 5 is not greater than 8 (this choice produces a "degenerate" triangle....one with "0" area)
Only the first choice is correct
Originally, we have ....(2/5) (4/9)
Let's look at each option
a) (5/5) x (4/9) = 20/ 45
b) (4/5) x (5/9) = 20/45
c) (3/5) x (6/9) = 18 / 45
d) (2/5) x (7/9) = 14 / 45
Notice that the last option minimizes the chances of a winner....!!!!
This is known as the "Triangle Inequality"...for our purposes here.....it says that the sum of any two sides of a triangle is greater than the remaining side.....
Knowing this......see if you can figure this out.....
Hint......the second choice is no good because 4 + 6 < 12.....!!!
2/3y=18 multiply both sides by 3/2
y = (3/2)*(18) simplify
y = 27
What are the choices???
The area of the "large" rectangle is given by
(2 + 3 + 2 + 3) * (6) =
(5 + 5 ) * (6) =
(10) * (6) = 60 cm ^2
And the area of the two small squares is (2 * 2) = 4 cm^2
So....the total area is (60 + 4) in^2 = 64 cm^2
The base is (10 in )^2 = 100 in^2
There are 4 triangles each having an area of (1/2)(10)(3) = 15 in^2
So 4 times this is 4 (15 in^2) = 60 in^2
So....the total surface area = (100 + 60) in^2 = 160 in^2
Triangular prism.....!!! ... both bases are triangles and the lateral sides are parallel....!!!
Correct .....!!!
