CPhill

Let x be the number of white hydrangeas and let y be the number of pink hydrangeas

So, in the first bed,  x + y = 45

And we want 2 times the number of white hydrangeas in the second bed as the first = 2x and 3 times the number of pink hydrangeas as in the first = 3y   so    2x + 3y = 120

Using the first equation, we can solve for y  by subtracting x from both sides  so   y = 45 - x

And substituting this for y in the second equation, we have

2x + 3(45 - x) = 120    simplify

2x + 135 - 3x = 120

-x + 135 = 120     subtract 135 from each side

-x = -15               multiply both sides by -1

x = 15    and y = 45- 15 = 30

So.....there are 15 white hydrangeas in the first bed and we need twice this number in the second bed = 30....so that's 45 total white hydrangeas

And there are 30 pink hydrangeas in the first bed and we need three times this many in the second bed = 90So that's a total of 120 pink hydranges

Nice, saseflower......

I assume that you might want to evaluate this.....

86.010*log(19.5)-70.041*log(75)+36.76  =   about 16.385

We have 12 "face" (picture) cards in a deck

So the total number of sets possible in dealing three cards out of 52 is just C(52, 3)  = 22100

And we are interested in choosing the sets containing any 3 of the 12 face cards = C(12, 3)  = 220

So....the probability is just    220 / 22100  = about .99%

Uh......it's a little more than 11 minutes ........!!!

Distance / Rate = Time     so

220miles / 40 miles per hr  = 5.5 hrs.

The total area of the board and frame is (40cm+ 8cm + 8cm) = 56cm on a side....so..... 56cm x 56cm = 3136cm^2

There are 32 maple squares on the chessboard and eah is 5cm^2.....so....their total area is 160cm^2

So      160cm^2  / 3136 cm^2 = 5/98 = about 5.1%

Thanks, Melody......

Sum the number of tiles he has to paint and then divide that by 450. If you get a "fractional" amount, round up to the next integer.

f must be degree 4.  Since it would contain an x^4 term, when this is multiplied by the x^2 term in the first expression, the result would be a 6th degree polynomial.

In essence, we need to multiply the "9" on the x^4 term in the second expression  by c such that, when this product is added to 5 on the x^4 term in the first expression, we get 0....therefore....

9c + 5 = 0      subtract 5 from both sides

9c = -5          divide both sides by 9

c = -5 / 9