(a) What is the probability that we draw 1 ace, 1 two, 1 three, 1 four, and 1 five (this is one way to get a "straight")?
In each case we want to select 1 of 4 cards from each of the specified ranks = [ C(4,1)]^5 = 4^5
And the total hands = C(52,5)
So.....the probability is just
4^5 / C(52,5) ≈ .000394 = .0394%
Note that these hands include the possibility of a straight flush ....
