CPhill

Thanks, Alan...I was assuming the questioner was asking for ending zeros.......

The Potrzebie, of course......Some prefer centimeters, but the Potrzebie is the much more functional - and better understood, internationally - term. It's flexibility for the measure of areas, volumes, etc. is also a desirable trait. It's generally defined as the thickness of the 26th issue of MAD Magazine and it equals about 2.263348517438173216473 mm.....give or take.......

I hope this helps.....(but it probably doesn't)

Excellent idea.....at the end of the week.....if we deem that ND and Aziz have worked hard enough......we might let them share the coffee and donuts with us......but only if they work hard enough.... and we'll be the final judges of that....I may give up my sunglasses easily, but I don't give up coffee and donuts so easily..!!!!!

There is a method for determining this.......I'm still working on the reason for why it works....maybe I'll "see the light" later on.  But here it goes......

1. Take the number (without the factorial part) and divide it by 5....discard any "remainder' ...so we have..

486/5 = 97.2 = 97

2. Divide the number by succesive powers of 5 that are greater than 1 until we get a "decimal" answer..add all the whole number parts of the results...once we get a "decimal' answer only, we can stop.

3. Therefore, the next power of 5 is 5² = 25. So dividing 486 by 25, we get....19.44 = 19

4. And the next power of 5 = 5³ = 125 . And dividing 486 by 125, we have .....  3.888 = 3

5. Dividing by the next power of 5, (5⁴ = 625), we have.....  .7776, and we can stop !!!

So adding all the "whole number" results, we have ...  

97 + 19 + 3 =   ..... 119 zeroes.....

And there you go......I hate to do things "cookbook style" without having a total understanding of the reasons, but, hey...my old brain just doesn't function as well as it used to!!!!

I think we can retire now, Melody!!!

It looks as if ND can handle the forum by himself............!!!!

Very nice, ND........!!!!

Poits and a Tumbs-Up !!!

Alternative question: What is the momentum generated by three forum members with a combined mass of "x" all moving at "y" meters per second to answer the same question???

Hint: It's definitely greater than the momentum of the cheetah and elephant combined!!!

Only answers converted to imperial minims will be accepted..........

OK......but see if you can answer some of them before you post......

This one might also be interpreted as.......

[√(6x^3) / √(3x)]  * √(8x^2) =

√(2x^2)   * √(8x^2) =

√(16x^4)  =

4x^2   ......In which case the answer is B.......(I kinda' think A might not be the correct answer because √16 could be simplified further......)

The lack of parenthesis and brackets in some of these questions makes it tough to discern what the intent might be......Parenthesis and brackets aren't just for "show"   !!!!!!