1) The tangent of the angle at any time is given by:
tan(θ) = y / 120 differentiating this with respect to time, t, we have
sec^2(θ) dθ/dt = (1/120) dy/dt (1)
When the helicopter is 90m above the ground, θ is given by
arctan(90/120) = about .6435 rads ....so....filling in the missing pieces in (1), we have
sec^2(.6435) dθ/dt = (1/120m) (2.5m/s)
dθ/dt = (1/120m) (2.5m/s)/ sec^2(.6435) = about .01334 rads/s
2) The area of the square = x^2
The perimeter of the circle = 100 - 4x = 2*pi*r
Therefore.....the radius of the circle is [50 -2x] /pi
So....the total area is given by :
A = x^2 + pi ( [50 -2x] /pi )^2 = x^2 + (1/pi) *(50-2x)^2
Take the derivative of this and set it to 0
A' = 2x - 2* (2/pi) [ 50 - 2x] =
2x + 8[x -25] /pi = 0
x + 4[x - 25]/ pi = 0
pi*x + 4x - 100 =0
x (pi + 4) = 100
x = 100 / (pi + 4) = about 14.002 cm
The second derivative =
1 + 4/pi .....since this is always positive, the curve is concave up at all points....so x = 14.002cm is a minimum
And this is a minimum as verified by the curve shown here : https://www.desmos.com/calculator/orqtlce6ju
The minimum total area is about 350.062 cm^2
