CPhill

The distance Solveit gave is correct.....however, the bearing  is given by :

arctan[250/100] = 68.2°  =  S68.2°W   [sometimes also expressed as (180 + 68.2)°  =  248°]

  -5x-7=8y      →  -5x - 8y = 7        (1)

   3y=-2x-9    →    2x + 3y  = -9     (2)

Multiply  (1)  by 3   and  (2)  by 8   and we have

-15x - 24y   =   21

16x + 24y   =  -72        add these

  x              =   -51

And using any equation - I'll use (2)  - we can find y

2(-51)  +  3y   = -9

-102 + 3y  = -9      add 102 to both sides

3y  =  93     divide both sides by 3

y =  31

[1/2 kg ] / 4   =  1/8 kg each

EXACTLY correct, DS   !!!!!

[ 4x - 1 ]  / [ x + 2]  =

[4x + 8  -  9 ] / [x + 2]  =    [split into separate fractions ]

[4x + 8] / [x + 2]   -  9/ [x +2]  =

4[x + 2] / [x + 2]   -  9/ [ x + 2]  =

4  -  9/ [x + 2]

500 rounds / 60 sec   =

50/6  per sec  =

25/3  per sec =

About  8 1/3  per second  [or, 8, rounded down  ]

Nice reasoning, Dragonslayer and guest  ..!!!!!!!

Titanchops......we are going to ban you from this site very soon......you're an idiot.....

5/2  - (4/5)(3/2)^2   =   [remember that we evaluate the exponent, first ]

5/2 - (4/5)(9/4)  =

5/2 - [4/4][9/5]  =

5/2  - [1] [9/5]  =

5/2 - 9/5          common denominator = 10

25/10  -  18/10  =

7/10    .....definitely!!!

Here's another way.....since the final exam counts twice as much as the others, we have

[63 + 75 + 72 + (2)80]  / 5   = 74