Pure ethanol couldn't have a concentration of "95%"....if it's pure, it's 100% ethanol....!!!!
And pure water has a concentration of 0% ethanol .......so.....let the amount of pure ethanol to be mixed = x
And....the amount of pure water = 500 - x .......and we have....
100x + 0 (500 - x) = 70 (500)
100x = 35000 divide both sides by 100
x = 350 ml of pure ethanol
And the amount of water = 500 - 350 = 150 ml
