3 / 3^3 = [3] / [ 3 * 3 * 3] = one 3 cancels on top/bottom = 1 / [ 3 * 3] = 1 / 9
21parts / 4 hrs = ? parts / 7 hrs cross-multiply
7 * 21 = 4 * ? divide both sides by 4
[ 7 * 21] / 4 = ? = 36.75 parts in 7 hrs
15% = .15 and "of" means "multiply"......so we have
.15 * 70 =
10.5
8 cos(x) − 4 = 0 add 4 to both sides
8cos(x) = 4 divide both sides by 8
cos(x) = 4/8
cos(x) = 1/2 and this happens at pi/3 and 5pi/3 on the requested interval
48 / 18 =
[ 8 * 6 ] / [3 * 6] = the 6s cancel on top/bottom
8 / 3
-1x > 15 divide both sides by -1 and reverse the inequality sign
x < -15
Assuming 150 is supposed to be 150m^2.....we have
45* 82 / 150 = 24.6 [or, 25 tins]
5-4 = 1/54 = 1/ [52 * 52] = 1 / [25 * 25] = 1/ 625
See the graph of the constraints, here : https://www.desmos.com/calculator/laixdb2hd8
There is only one corner point [vertex] at (400,500)
The max profit will be :
P = 14(400) + 22(500) - 900 = $15700
96,97,98,99,100,101,102,103,and 104 =
Each of the first 4 terms written in reverse order and paired with the last 4 terms will produce a sum of 4(200)
Adding the middle term - 100 - produces 4(200) + 100 = 800 + 100 = 900