I'll see what I can do......
We need to find the number in the intersection, first....and we have
P(M or E) = P(M) + P(E) - P(M and E)
300 = 250 + 220 - P(M and E)
P(M and E) = 250 + 220 - 300 = 170
Here's the Venn diagram :

b). the student takes Math 128, given that the student takes only one class
130 students only take one class.......and 80 of these take Math 128 only....so 80/130 = 8/13
c). the student takes English, given that the student takes Math 128
250 students take Math 128......and of these 170 also take English......so 170/250 = 17/25
d). the student takes Math 128, given that the student takes English
220 take English.....and of these 170 also take Math 128 ......so 170/220 = 17/22
e). the student takes neither, given that the student does not take Math 128
The number not taking Math 128 = 50 plus the 20 taking neither = 70 ........and there are 20 taking neither [none].....so 20/70 = 2/7
[Melody or Alan.....could you check these answers???......I'm not totally confident about these]
