There were m visitors in an exhibition on the first day and 1200 fewer visitors on the second day. On the third day, the number of visitors was 30% greater than the number of visitors on the second day. What was the average number of visitors over the three days?
1st day = m
2nd day = m - 1200
3rd day = the number the second day plus 30% more = [m - 1200] + .30[m - 1200] = (1.30)[m- 1200]
So....we add the attendance over 3 days and divide by 3 and we have
[m + ( m- 1200) + (1.30)( m - 1200) ] / 3 we could leave it like this, but let's simplify
[2m - 1200 + 1.30m - 1560] / 3 combine like terms on the top
[3.3m - 2760] / 3 note that we can write this as :
[3.3m ] / 3 - 2760/3 =
1.1m - 920
I see where you got confused......I made a slight error in my first post by keeping the "divided by 3" part in at the last.....I'll edit that out right now.....!!!!!
Does that help???
