I'm not sure as to what you're calculating, but, if we're asking the probability of a 7 or the probability of a double, we have :
P ( 7 or a double) = P(7) + P(double) - P(7 and a double)
The last term is 0.......no doubles equal 7
P(7) .......there are 36 possibilities when we roll 2 dice........the probability of a 7 = 6/36 ....and the probabilty of a double = 6/36
So
P(7 or a double) = 6/36 + 6/36 - 0 = 12/36 = 1/3
