Here might be a slightly easier approach
log7 (x) + log7 (x + 6) = 1
Note that we can write 1 as log7(7)
And using a log property, we can write the left side as log7 [ x * (x + 6)] ....so we have
log7 (x * (x + 6) ] = log7(7) and we can get rid of the logs and solve this equation :
x * (x + 6) = 7
x^2 + 6x = 7
x^2 +6x - 7 = 0 factor
(x + 7) (x - 1) = 0 and setting both factors to 0, we have that x = 1, or x = -7
We must reject the second solution because it requires taking the logs of negative numbers in the original equation, and this is not defined........so, the aswer is ..... x = 1
