CPhill

The ascent angle is given by :

tan^-1  [ 16/100 ] = about 9.09°

And the elevation change is given by

 700 * sine (9.09)   = about 110.59 m

Slope  = 

  [ subtract the y coordinates in some order ]  /  [ subtract the x coordinates in the same order]

So we have

[  - 1 - 11 ] /  [ -2 - 4 ]   =  -12 / - 6     =  2

(1/4x7/8)x16     ........  this can be re-ordered as :

(1/4) x 16 x 7/8   =

4 x 7/8   =

28/8 =  7/2

Area_rhombus  = side length * height  

The side length  = 4m   and   the height =  3m

So the area =  4 * 3   = 12m^2

On a unit circle, a 90“ angle would have its endpoint located at  (x, y)  = (0, 1)

Since r = 1  and x = 0......cos [ theta]  = x / r     ......so  ......cos [ 90]   = 0 / 1    =  0

This is a linear equation  in the form y = mx + b........I'm not familiar with an exponential scatter plot, but, there may be such a thing......!!!!!

I'm assuming something like a lawn mower blade......Each second it travels   2pi*(10in) * 2500 / 60 = about  2618  in  =   about 218.66 ft/sec

And 60mph = 88ft/s....so

m / 218.66  = 60 / 88     where m is the speed in mph........

So.......m = (218.66) * (60) / 88 = about 148.75 mph

( 3 /14) (3 / 14)    =   9 / 196

Area = L x W.......so we have

Area = [ 2x - 3 ] * 5   = [10x - 15 ] sq ft    ........we would have to know the value of x to give a "numerical answer"

(2^3)^4/3  =

(8)^4/3 =

(8 ^1/3) ⁴ =

(2) ⁴   =

16