CPhill

Zero is considered to be an "unsigned" quantity.....thus, -0 = +0  = 0

And   ...   sqrt(0)  = 0

1km = 1000 m

So

2.4km = 2400m

(3 / 4) + (1 /5)n = (1/2)        subtract 3/4 from both sides

(1 / 5)n =   1/2 - 3/4            →  1/2  -  3/4   = 2/4 - 3/4   = -1/4

(1/5)n = -1/4       multily both sides by 5

n = -5/4

Multiply top and bottom by the conjugate of 7 - 6i  = 7 + 6i and we have

[ 8 + sqrt(2)i] [ 7 + 6i] /  ( [7 - 6i] [7 + 6i]  )  =

[56 + 7sqrt(2)i + 48i - 6sqrt(2)] /  [49 - 36i^2 ] =

[56 + 7sqrt(2)i + 48i - 6sqrt(2)] / 85

Multiply the top and bottom by the cojugate of 4 - 9i  = 4 + 9i, and we have:

8[4 + 9i] / [16 + 81] =      

[32 + 72i ]  / 97

C is the one that is true.

Notice that, when y changes by 2, x changes by 1.......so the "constant of variation" is just the slope which is  :  change in y / change in x   = 2/1 = 2

So.....using the point (7, 11) and the slope....we can write the general equation  using the slope-intercept form as :

y =(2)(x - 7) + 11    simplify

y  = 2x - 14 + 11

y = 2x - 3

Prime factorization   = 2 x 5²

The same thing that it is WITH a calculator......!!!!!!!

W = Area/Length  = 4225 / 5      I'll let you take it from there  !!!!!