6q + 12r + 3q - 11r again, since we are just adding and subtracting, we can rearrange the terms as:
6q + 3q + 12r - 11r =
9q + 1r
No prob......!!!!
12b - 4c + 3b - 2c = combine like terms
12b + 3b - 4c - 2c =
15b - 6c
( 1 + 7/9) / 2 =
(16/9) / ( 2 / 1) = invert the fraction in the denominator and multiply
(16 / 9) * ( 1 / 2) = rearrange as
(16 / 2) * ( 1 / 9) =
16 / 18 =
8 / 9
5 / 6 = n / 72 cross-multiply
72 * 5 = 6 * n simplify
360 = 6n divide both sides by 6
60 = n
84 = 2^n * m * p = 2^2 * 3 * 7 n = 2 and either m = 3 and p = 7 or vise-versa........
A critical point is usually defined as a point on a graph of a curve where the derivative of the function = 0 or where the derivative does not exist.........note that the point must actually exist....!!!!
40 = 2^m *n = 2^3 * 5 = 8 * 5 .... so......m = 3 and n = 5
2.7 + 3.2 -5.3 * 1.1 = 0.07
This site........http://www.alcula.com/calculators/statistics/linear-regression/
calculates it as :
y=24.46849349439+0.019140470984623x
