Let P be the orginal price.....then we have
P - .05P = 3.3174
.95P = 3.3174 divide both sides by .95
P = 3.3174/.95 = 3.492
b < 17
If you bought 17 pieces of candy and ate fewer than 17 of them, b might represent the number you ate
Or, if this is supposed to be
17 - b
Then this might represent the number you had left after eating "b" pieces
(2x^3-10x^2+x-5)/(x-5) factor the numerator by grouping
[(2x^2)(x - 5) + 1(x -5)] / (x - 5) =
[ (2x^2 + 1) (x - 5) ] / (x - 5) = "cancel" the (x - 5) in numerator and denominator
2x^2 + 1
The second one
Enter it like this:
sqrt((15.5)*(15.5-6)*(15.5-11)*(15.5-14))
Looks like Heron's Formula....the answer is about 31.527 sq units
1/3(5x+3)>-14 multiply both sides by 3
5x + 3 > -42 subtract 3 from both sides
5x > -45 divide both sides by 5
x > -9
( 2 + 2/3) - (1 + 5/9) =
(2 + 6/9) - (1 + 5/9) =
24/9 - 14/9 =
10/9 =
1 + 1/9
Divide money available by the cost of each uniform......so
14,500 / 258 = 56.2 uniforms.....but........since we can't purchase .2 of a uniform.....call it 56 uniforms
On the onsite calculator, type,...... abs(number ) and hit " = "
(1/2) [ 1/4 + 1/8] =
(1/2) [ 2/8 + 1/8] ]
(1/2)(3/8} =
3/16
