fixed it.
Fixed
Working off of \(3x^2=x^4+1\)
We add 2x2 to both sides
\(3x^2+2x^2=x^4+2x^2+1\)
Factor
\(5x^2=(x^2+1)^2\)
Divide both sides by \((x^2+1)^2\)
We get:
\(\frac{5x^2}{(x^2+1)^2}=1\)
Divide both sides by 5.
and you get your answer of \(\boxed{\frac{1}{5}}\)
eh?
Wha is that supposed to be?
You sure you typed that correctly?
What do you mean by
"If \(x^2+\frac{1}{x^2}\)"
Is it equal to something..?
EP proved that there is nothing wrong with picture posting.
both j & k are positive integers
The question says that j and k have to be positive.
This is why it doesn't work, becuase when you add three to both sides, j and k become 0.
0 is neither positive or negative. So 0 is not a solution
Post the real image please.
But how
I don't know.
Omi's solution might be even simpler using trig!
MY IQ IS sooo low.
I just realized that the solution DOES NOT match your problem!
However, they use different numbers but ask the same question, so you should get the correct answer using Omi's or AoPs's method.
+2864 
