BuilderBoi

Common Ratio: \(1 \over 10\)

The fifth term is: \(2 \times {1 \over 10}^4 = \color{brown}\boxed{0.0002}\)

It is easier to count for what we don't what and subtract that from 1. 

The probability that there will 0 days of snow is: \({1 \over 2}^3 \times {2 \over 3}^4 = {2 \over 81}\)

Thus, the probability that it will snow for at least 1 day of the week is: \(1 - {2 \over 81} = \color{brown}\boxed{79 \over 81}\)

Thanks!

There are \(2^4\) ways of flipping the coins. 

There are 3 ways to get at least 3 heads in a row: THHH or HHHT or HHHH

Thus, the probability is \(\color{brown}\boxed{3 \over 16}\)

ig my name is cphill now ¯\_(ツ)_/¯

Because of the shape of a circle, both the points have to be the same distance from the center. 

Using the Pythagorean theorem, we can write this as an equation: \(\sqrt{(2-x)^2 + (3-y)^2} = \sqrt{(3-x)^2+(2-y)^2}\)

Substituting 0 for y, we get: \((2-x)^2 +9 = (3-x)^2+4\)

Solving, we find \(x = 0\), meaning the coordinates of the center are: \((0, 0)\)

Using the Pythagorean Theorem, we find that the radius of the circle is \(\color{brown}\boxed{\sqrt{13}}\)

Keep trying!!! With hard work and determination, you will get there!!

Draw points A and B at the 2 intersection points of the circle.

 The circular sector \(ABP\) has an area of \({144 \over 4} \pi = 36 \pi\)

The isoceles triangle has area \(12 \times 12 \div 2 = 72\)

This means that the area of half the sector is \(36 \pi - 72\). Multiply this by 2, and we find the circular sector has an area of \(\color{brown}\boxed{72 \pi - 144}\)

No, our answers are the same... I just did mine in decimal, and Chris did his in fraction form.

you tell me... are the answers the same or different?