Alan

Googol = 10^100

Googolplex = 10^Googol

Finding the inverse value, f^-1(14), doesn't require you to find the complete inverse function relationship.  See what you get when you calculate the value of f(7).

I'm assuming f(x) = 7 + x + ln(x - 6)         ( i.e. with ln(x - 6) not ln(x + 6) )

" ...Sikorsky UH-60A helicopter ... "

You would never be able to create a sensible graph with this data by plotting N/m^2 with 1 N/m^2 grid lengths on the x-axis!  You could do it if you scaled the values by 10^7 or 10^8 perhaps.

Let one angle be x.  The other is 17x.

So:   x + 17x = 90

You can take it from here,

"Noa drove from the Dead Sea up to Jerusalem, and her altitude increased at a constant rate of 740 meters per hour. When she arrived in Jerusalem after 1.5 hours of driving, her altitude was 710 meters above sea level. Let A represent Noa's altitude (in meters) relative to sea level after t hours. Complete the equation for the relationship between the altitude and number of hours."

Let t = time in hours:

A = 740*t + k

710 = 740*1.5 + k

710 = 1110 + k

k = 710 - 1110 = -400

A = 740*t - 400

As follows:

"...So the mass of A is 23 1/3 grams..."

Err, not exactly!   Mass of A =   0.5787037037 * 6912 grams

Check the answer given at : https://web2.0calc.com/questions/math-problem_67#r1 where you first asked it.  Don't repeat a question without checking the original!

NB Geno made a slight mistake by inverting the ratio on the RHS. 

Areas scale as length squared, whereas volumes scale as length cubed.  So the volume ratio varies as the cube of the square root of area ratio.

i.e.  \(\frac{V_A}{V_B}= (\frac{A_A}{A_B })^{3/2}\)

Mass scales with volume, so \(\frac{M_A}{6912}=(\frac{28}{40.32})^{3/2}\) 

I'll leave you to crunch the numbers.