Let y = 2x then we have 4y + 2y = 56. (And x = log2y)
Now 4y → (22)y → (2y)2
Let z = 2y, so now we have z2 + z = 56 or z2 + z - 56 = 0. (And y = log2z)
This factorises as. (z + 8)(z - 7) = 0
Hence: z = 7, y = log27, x = log2(log27)
We can't have logs of negative numbers (as long as we aren't considering complex numbers) so this is the only solution.