Was ergibt 3ab*a²b*4a³b³?

3ab*a²b*4a³b³  = $${\mathtt{12}}{\mathtt{\,\times\,}}{{\mathtt{a}}}^{{\mathtt{6}}}{\mathtt{\,\times\,}}{{\mathtt{b}}}^{{\mathtt{5}}}$$

Gruß radix !

$${\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{ab}}{\mathtt{\,\times\,}}{{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,\times\,}}{\mathtt{4}}{\mathtt{\,\times\,}}{{\mathtt{a}}}^{{\mathtt{3}}}{\mathtt{\,\times\,}}{{\mathtt{b}}}^{{\mathtt{3}}} = {\mathtt{12}}{\mathtt{\,\times\,}}{{\mathtt{a}}}^{{\mathtt{6}}}{\mathtt{\,\times\,}}{{\mathtt{b}}}^{{\mathtt{5}}}$$

((12*a^5)*ab)*b^4