two dice are rolled. what is the probability that the total number achieved is greater than 4 but less than or equal to ten?

Probabiltiy  of 5 =  4/36

Probabiltiy  of 6  = 5/36

Probabiltiy  of 7  = 6/36

Probabiltiy  of  8  = 5/36

Probabiltiy  of 9 = 4/36

Probabiltiy  of 10 = 3/36

So  ...the probabilty of > 4  but ≤ 10  =   [ 4 + 5 + 6 + 5 + 4 + 3 ] / 36 = 27/36 =  3/4

two dice are rolled.

what is the probability that the total number achieved

is greater than 4 but less than or equal to ten?

$\color{green}{\text{In green dice one}}\\ \color{blue}{\text{In blue dice two}}\\ \color{red}{\text{In red the total number } >4 \text{ and } \le 10 }$

$\begin{array}{|r|r|r|r|r|r|r|} \hline + & \color{blue}1 & \color{blue}2 & \color{blue}3 & \color{blue}4 & \color{blue}5 & \color{blue}6 \\ \hline \color{green}1 & 2 & 3 & 4 & \color{red}5 & \color{red}6 & \color{red}7 \\ \hline \color{green} 2 & 3 & 4 & \color{red}5 & \color{red}6 & \color{red}7 & \color{red}8 \\ \hline \color{green}3 & 4 & \color{red}5 & \color{red}6 & \color{red}7 & \color{red}8 & \color{red}9 \\ \hline \color{green}4 & \color{red}5 & \color{red}6 & \color{red}7 & \color{red}8 & \color{red}9 & \color{red}10 \\ \hline \color{green}5 & \color{red}6 & \color{red}7 & \color{red}8 & \color{red}9 & \color{red}10& 11 \\ \hline \color{green}6 & \color{red}7 & \color{red}8 & \color{red}9 & \color{red}10& 11& 12 \\ \hline \end{array}$

$\text{The probability of } > 4 \text{ but } \le 10 \text{ is } \dfrac{27}{36} \text{ or } 75\ \%$