A dice is rolled twice. What is the probability of observing at least one five?
Melody is correct......
Here is another way to look at it
Probability of NOT rolling a 5 on the first roll is 5/6
Probability of NOT rolling a 5 on the second roll is also 5/6
Probability of NOT rolling a 5 in two rolls is then 5/6 x 5/6 = 25 /36
so the probability of (YES) rolling a 5 is 36/36 - 25/36 = 11/36 with two rolls....
One of these days I will understand probability.....'probably'? or Maybe ? LOL
(I think !)
Each time you roll the die (one is a 'die' ...two are called 'dice') you have a 1/6 chance of rolling a '5'
rolling TWO times DOUBLES that chance 2 x 1/6 = 1/3 chance of rolling a '5'
A dice is rolled twice. What is the probability of observing at least one five?
P(first one 5 )+P(both 5) - P(both 5)
I'm going to try doing it a couple of different ways and see I get the same answers :)
16+16−16∗16=1266−136=1136 or16∗56+56∗16+16∗16=536+536+16=1136
Melody is correct......
Here is another way to look at it
Probability of NOT rolling a 5 on the first roll is 5/6
Probability of NOT rolling a 5 on the second roll is also 5/6
Probability of NOT rolling a 5 in two rolls is then 5/6 x 5/6 = 25 /36
so the probability of (YES) rolling a 5 is 36/36 - 25/36 = 11/36 with two rolls....
One of these days I will understand probability.....'probably'? or Maybe ? LOL
(I think !)