If H=10, then the following is true:
Notice that TEAM contains MAT in it. So you can take out the MAT and replace it with 25.
Putting this value of E into MEET gives the following:
Going back to the first one, you can see that MAT contains MT. Substituting the value found for M+T into MAT gives this:
Answer: \(2\sqrt6\) and \(-2\sqrt6\)
Multiplying both sides by 3y gives:
\(y^2 + 3y = 3y + 24\)
Subtracting both sides of the new equation by 3y gives:
\(y^2 = 24\)
Isolating y gives:
\(y = \pm \sqrt24\)
The square root of 24 can be simplified into \(2\sqrt6\). So y can be \(2\sqrt6\) or \(-2\sqrt6\).