Thanks for the help! I figured out the answer! :)

I multiplied everything by (a+b+c)(a+b)(a+c) and simplified it to where there is only one term on one side that is squared because that is like the cosine rule.

Do the upvotes and downvotes really matter that much??

I am sorry if they do.

So BC is \(\sqrt{19}\).

Then, by the law of sines, sin BCP is \(\frac{\sqrt3}{\sqrt{19}}\).

What now?

Sorry, but this answer is incorrect. Can you show how you got that?

I expanded it to \(a^2-2ab-2ac-b^2-c^2-bc=2a^2\).

I don't know how to compare that to the law of cosines: can I simplify further?

1) How would I find BC?

Taking the square root of 169, you get y = 13.

But we also have to remember that y can be negative, giving us that y = -13.

So our answers are y = 13, and y = -13.

Thank you so much! This makes a lot more sense!

Sorry, that isn't correct. In case you missed it, the lengths 10 and 24 are the lengths of the diagonals.

Sorry, it's wrong, b means base b, not multiply by b

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Thank you! :)

It says necessarily divisible by, so every number possible has to be divisible by it, I was confused there too. Thank Y'all for helping me!

Same with mine :D

You made a quick mistake forgetting the 1, but I caught it. Thank you for leading me in the right direction. :)

They are all the same, but if you take a number's reciprocal and square it by the number, and the number is a power of 2, you get the square root of 2, NOT 1. This is because when you simplify the other equations, you get the square root of 2, every single time under these conditions. Remember, fractions as exponents are square roots to the power of the reciprocal of the fraction. Therefore they are all the same. Around 1.41421356237 ish, but the decimal never ends.

-MathCuber

I get it, Thank you!

I figured it out... NVM

Thank you for trying. But I still need help