lhyla02

Hey there.

Here we have 2 unknowns and 2 variables so you need two equations.

Let x=number of adult tickes purchased

Let y=number of student tickets purchased

we know that 1181 tickets were sold and $2845 was raised. Given that we get the two equations:

x+y=1181

5x+y=2845

Here we can use elimation by taking the first equation from the second:
 

4x=1664

x=416 adults

Now you sub this back in to get y:
 

416+y=1181

y=765 students

Thus you have 416 adult tickets and 765 student tickets

Hope this helped :)

Hey there!

Here we know 2 angles of the left triangle will be 75 and 45. using this, the bottom right angle will be 60

Now we can find the bottom left angle of the triangle on the right, which will be 41.

Again, since a triangle has 180 degrees alltogether, the bottom right angle of the right triangle will be 71.

Finally, using this you know that ?=180-71=109

Hope this helped :)

\(\frac{4645*598}{58598}-565+265\approx-252.6\)

Oh that was a doozy haha! My bad

I thought it was window!!!

Hey there!

First you must find what the angles are. Angles \(KJL\) and \(MLN\) are equal, we can use this to find \(x\),

\(6x-2=5x+10\)

\(x=12^o\)

Using this you now know what all angles are going to be:

\(KLJ=70^o,MLN=70^o, NML=65^o, KJL=60\)

Also using the knowledge that there is \(180^o\) in a triangle you can find the last 2 angles:

\(JKL=180-70-60=50^o\)

\(MNL=180-70-65=45^o\)

Finally you can use this to find the true statements that you have provided.

Let me know how you go :)

No problems, Glad to help :)

Hey there!

Since the Parralelogram is 5 units high, you can use Pythagoras (\(C=\sqrt{A^2+B^2}\) to gather the length of the slanted sides.

Perimiter = Top + Bottom + 2 Slanted Sides = \(4+4+\sqrt{5^2+1^2}\)

Thus your Perimeter is:

\(4+4+5.1\approx13.1 units\)

Hope this helps :)

Hey there!

This can be altered using exponential laws like so:

\(2^{3x^{2}+2x}=2\)

Taking the logarithm of both sides produces the following.

\(3x^2+2x=1\)

\(3x^2+2x-1=0\)

From this, use the quadratic formula (\(x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\)), where \(a=3\), \(b=2\), \(c=-1\). This will give you the two \(x\) values you are looking for!

Let me know how you get on :)

Hey there!

Here you want to use Tangent, or Tan for short, and rearrange to give your angle.

\(Tan(\theta)=\frac{Opposite}{Adjacent}=\frac{16}{10}\)

\(\theta =Tan^{-1}(\frac{16}{10}) \)

\(\theta\approx58 degrees\)

Hope this helped :)