Dragan

In the diagram below, triangle ABC is isosceles, and triangle MPQ is equilateral. Find the area, in cm2, of triangle MPQ.

BM = 36 cm

AC = BC

PC = QC

Let an F to be the foot of altitude from M to BC

∠FMP = 15°

FM = sqrt [( 36² )/2] = 25.455844

MP = FM / cos(15°) = 26.353829

PQ/2 = MP/2 = 13.1769145

The height of ΔMPQ is H = tan(60°) * (PQ/2) = 22.8230854

Area of  Δ MPQ = (PQ/2) * H = 300.7378467 cm²  

Yours too, Melody!  

Q  (16, 0)

T   (8, 0)

W  (10, 12)

P   (12, 24)       ( P is 'somewhere over the rainbow' )  

R   (6, 12)

S   (14, 12)

Nya selects a tile for her shower that is in the shape of a rhombus. Each side of the rhombus measures 6 inches. The diagonal opposite the smaller angle is 4.6 inches.What is the measure of the larger angle in the rhombus?

Larger angle θ ≈ 134.9°  

AD = 3.5

ND = 1.75

BD = 3.13

DG = 2.97

FG = 0.99

DE = 2.475

EG = 0.495

Area of  Δ DFG = 1.47 u²

Area of  Δ EFG = 0.245 u² 

Area of  Δ DEF = 1.225 u²     

Hi CPhill ! Your answer differs from mine, and I can see why.

You've calculated the height using square's diagonal instead a side of it. 

The rope should be cut according to this ratio:       1 : 5 : 10

Therefore, the length of the 3rd rope is:            48 / 16 = 3 ft    

Hi Guest, your answer is correct!  

No, I did not need the answer. I'm on this forum for fun, and to keep my mind occupied. 

But, if there's a problem, I wont post the questions anymore.  

What about this...?     56 / 4 = 14