Davis

x=2n, y=12-5n, z=3n-4 for any n

tangent is cyclic

so the value of tangent is cyclic

so its converges to invinity

it converges to cot(1)-cot(sqrt(m+1))

Thanks!

Thanks!

What about complex numbers? Sorry, I did not make it clear that \(z\) could be a complex number. Thanks!

Thanks!

On this website, click the Home button. Then, go to the calculator and type in sqrt(88^2-2*32.2*125*0.85)

Since |a-n|= |a - b| + |b - c| + |c - d| + .... + |m-n| and |n-a|=|m-n| + |n-o| + ... + |x - y| + |y - z| + |z - a|, and |a-n|=|n-a|, The maximum value of |a-n| is 10

|b - c| + |c - a|>=|a - b|,the maximum |a-b| can be is 10

thanks!

We need to find how many factors of seven all the integers from 1 to 1000 have.

Each integer from 1 to 1000 can be a factor of 7, 49, or 343, giving it 1 factor of 7, 2 factors of 7, or 3 factors of 7. 

There are \(\lfloor\frac{1000}{7}\rfloor=142\) numbers that have 1 factor of 7.

There are \(\lfloor\frac{1000}{49}\rfloor=20\) numbers that have 2 factors of 7.

There are \(\lfloor\frac{1000}{343}\rfloor=2\) numbers that have 3 factors of 7.

So, the answer is \(2\cdot3+20\cdot2+142\cdot1\).

But, wait!

We are counting numbers that have 2 factors in the numbers that have 1 factor of 7!

And, we are counting numbers that have 3 factors in the numbers that have 2 factors and the numbers that have 1 factor!

So, the answer is \(2\cdot3+20\cdot2+142\cdot1-2-2-20=2+20+142=164\)!

Thanks!

How did you get that equation that would give you the largest value of a?

Also, why can't OB = 2, for example?

Since b^2-4ac = -3 for \(x^2-7x+13\), that means \(x^2-7x+13\) has no zeroes.

So, the domain of \(f(x)=\frac{1}{x^2-7x+13}\) is R.

16+16*3/4+16*3/4+16*9/16+16*9/16+16*27/64

=64.75 meters

Because both the leading coefficients of f(x) and g(x) are 1, the x^6 term would cancel out, giving a maximum degree of 5.

You can draw a Venn Diagram showing the first class, the second class. and the third class.

Since the first two classes averaged 83%, the first class averaged 80% and the second class averaged 85%, we can calculate the overlap between the classes. The average of students in two classes can be calculated by adding the first class's and the second class's averages together, then subtracting the overlap. So, the overlap of the first two classes is 83*2-80-85=1%. 

We can do the same thing for the second and third class. The overlap of the second and third class is 87*2-85-89=0%. So, no students go to the second and third classes. Since we also need the overlap between the third and first class and that information is not provided in the question, there is not enough information to calculate the average of all three classes.

Thanks!