y=16x+44 and y= -x^2+8x+28 finding it in elimination

y=16x+44 and y= -x^2+8x+28 finding it in elimination

$$\boxed{ \\ y=16x+44 \qquad y= -x^2+8x+28 }\\\\ \begin{array}{rcl} y = 16x+44 &=& -x^2+8x+28 \\\\ 16x+44 &=& -x^2+8x+28 \\\\ x^2+16x-8x+44-28&=&0\\\\ x^2+8x+16&=&0\\\\ (x+4)\cdot(x+4) &=& 0 \\\\ x &=& - 4 \\ \\ \hline \\ y &=& 16\cdot (-4) + 44 \\\\ y &=& -64+44 \\\\ y &=& -20 \end{array}$$

x = -4   and y = -20

Thanks Heureka

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