x^3+x^2+2x+2 factor by grouping so it ends up with two binomials.

x^3+x^2+2x+2 factor by grouping so it ends up with two binomials.

$$\small{ \text{Formula:} $ \boxed{a+ax+x^2+x^3 = (1+x)(a+x^2)} \\\\ $ \text{Example: } $\\$ a=2 \qquad 2+2x+x^2+x^3 = (1+x)(2+x^2) \\ a=1 \qquad 1+1x+x^2+x^3 = (1+x)(1+x^2) $ }$$

You have to play around with it a bit (or a lot) using trial-and-error trying different possibilities until it works.

Check your answer here: http://m.wolframalpha.com/input/?i=factorize+x%5E3%2Bx%5E2%2B2x%2B2&x=0&y=0

This factorization could be handy to remember.  Thanks Heureka.