(x-3-5i)*(x-3+5i)?
(x-3-5i)*(x-3+5i) ?
Formula:
z⋅ˉz=(a+bi)(a−bi)=a2+b2=|z|2
[(x−3)−5i]⋅[(x−3)+5i]=(x−3)2+52=x2−6x+9+25=x2−6x+34