x²-2x- 8 = 0 solve by factorising quadratic equation

x²-2x- 8 = 0 solve by factorising quadratic equation

$$\\(-2)*(+4) = -8 \\ (-2) +4 = 2\\ \boxed{(x-4)(x+2) = x^2-2x-8=0 } \\ x_1 = -2\\ x_2 = 4$$

$${\left({\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{1}}\right)}^{{\mathtt{2}}} = {{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}$$

if you write your equation as this: $${\left({\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{1}}\right)}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{9}}$$

you can use this rule: $${{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{{\mathtt{b}}}^{{\mathtt{2}}} = \left({\mathtt{a}}{\mathtt{\,-\,}}{\mathtt{b}}\right){\mathtt{\,\times\,}}\left({\mathtt{a}}{\mathtt{\,\small\textbf+\,}}{\mathtt{b}}\right)$$

finally you can write your  equation as: $$\left(\left({\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{4}}\right){\mathtt{\,\times\,}}\left({\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}\right)\right)$$

so this means: 4 and -2 are your solutions. I hope I could explain