X^2+x-6=0

X^2+x-6=0

$\begin{array}{rcl} x^2+x-6 &=& 0 \\ (x +3 )(x - 2 ) &=& 0 \end{array}$

$x = -3 \quad \text{ or } \quad x = 2$

Solve for x:
x^2+x-6 = 0

The left hand side factors into a product with two terms:
(x-2) (x+3) = 0

Split into two equations:
x-2 = 0 or x+3 = 0

Add 2 to both sides:
x = 2 or x+3 = 0

Subtract 3 from both sides:
Answer: |     x = 2               or x = -3