x = 0.0001

(x^2 - 1)/lnx+x-1= 0

(x² - 1) / lnx + x -1=0

x is not defined.

$f(x)=\dfrac{x^2-1}{\ln x}+x-1\\ f(0.0001)=\dfrac{(0.0001)^2-1}{\ln (0.0001)}+0.0001-1$

= -0.8913263806099232