What is the value of f(2)?

$f\left(\dfrac 1 x\right)+\dfrac 1 x f(-x) = 2x ~;\text{now let }x \to -\dfrac 1 x \\ f(-x) -x f\left(\dfrac 1 x\right) = -\dfrac 2 x~; \text{and multiply by }\dfrac 1 x \\ \dfrac 1 x f(-x) - f\left(\dfrac 1 x\right) = -\dfrac{2}{x^2}$

$\text{now add this to the original equation }\\ \dfrac 2 x f(-x) = 2x - \dfrac{2}{x^2} = \dfrac{2x^3-2}{x^2} \\ f(-x) = \dfrac{x^3-1}{x} = x^2 - \dfrac 1 x\\ f(x) = x^2 + \dfrac 1 x$

$f(2) = 2^2 +\dfrac 1 2 = \dfrac 9 2$