I assume you want the sum of the vertex angles of a regular pentagon.
The measure of one of the vertex angles is given by (n-2)*(180)/n where n is the number of sides of the pentagon.
So we have (5-2)*(180)/5 = 3(36) = 108º
And since we have 5 of these, then 5(108º) = 540º
And that's it !!!