What is the rectangular form of 𝑟^2=4𝑟sin𝜃+5

Hello can i get some help on how to transform
this equation from a polar coordinate system
to a rectangular coordinate system
step by step please

$r^2=4r\sin(\theta)+5$

Formula:
$\boxed{\sin(\theta)=\dfrac{y}{r}~ \text{or}~ y=r\sin(\theta)\\ r = \sqrt{x^2+y^2}}$

$\begin{array}{|rcll|} \hline r^2 &=& 4r\sin(\theta)+5 \\ x^2+y^2 &=& 4y+5 \\ \mathbf{x^2+y^2-4y-5} &=& \mathbf{0} \\ \hline \end{array}$